需求:显示最新的3条帖子(要求同一用户只取最新一条)
方法一:先排好序,再group by 达到同一用户只取最新一条(注意,MYSQL5.7版本的子查询的排序需要加LIMIT 排序才有效:引用)
SELECT * FROM ( SELECT t1.*, t2.nick_name, t2.head_portrait FROM tb_circle_post t1, tb_user t2 WHERE t1.user_id = t2.id AND t1.is_delete = 1 ORDER BY t1.create_time DESC, t1.likes DESC LIMIT 0, 50 ) temp GROUP BY user_id ORDER BY create_time DESC, likes DESC LIMIT 0, 3
方法二:使用DISTINCT的这种写法莫名其妙地 子查询的排序生效
SELECT temp.* FROM ( SELECT DISTINCT ( t1.user_id ), t1.order_amount, t1.create_time, t2.nick_name, t2.head_portrait FROM tb_order_goods t1, tb_user t2 WHERE t1.user_id = t2.id AND t1.is_delete = 1 ORDER BY t1.create_time DESC ) temp GROUP BY temp.user_id ORDER BY temp.create_time DESC LIMIT 0, 3
方法三:前两种方法都有不确定性:就是子查询的排序是否在最后一层查询中生效(具体可能需要explain查看执行计划)
最后的方法我也是觉得最合理的。
先子查询查出每个用户发帖子的最新时间,再用这个时间和用户ID去查多一次帖子表。
SELECT t.* FROM ( SELECT user_id, max(createTime) AS max_createTime FROM t GROUP BY user_id ) t2 LEFT JOIN t ON t.user_id = t2.user_id AND t.createTime = t2.max_createTime ORDER BY t2.max_createTime DESC LIMIT 3