计算原理:根据勾股定理算两个坐标直线距离
java版本
package com.application.util;
/**
* 地图坐标距离计算
*
*/
public class LocationUtils {
private static double EARTH_RADIUS = 6378.137;
private static double rad(double d) {
return d * Math.PI / 180.0;
}
/**
* 通过经纬度获取距离(单位:米)
* @param lng1 经度1
* @param lat1 纬度1
* @param lng2 经度2
* @param lat2 纬度2
* @return
*/
public static double getDistance(double lng1, double lat1, double lng2,
double lat2) {
double radLat1 = rad(lat1);
double radLat2 = rad(lat2);
double a = radLat1 - radLat2;
double b = rad(lng1) - rad(lng2);
double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2)
+ Math.cos(radLat1) * Math.cos(radLat2)
* Math.pow(Math.sin(b / 2), 2)));
s = s * EARTH_RADIUS;
s = Math.round(s * 10000d) / 10000d;
s = s*1000;
return s;
}
public static void main(String[] args){
double lng1 = 116.434395;
double lat1 = 39.862268;
double lng2 = 116.434651;
double lat2 = 39.862542;
double distance = getDistance(lng1,lat1,lng2,lat2);
System.out.println("distanc:"+distance);
}
}
sql版本
SELECT
*, ROUND(
6378.138 * 2 * ASIN(
SQRT(
POW(
SIN(
(
39.862542 * PI() / 180 - y_latitude * PI() / 180
) / 2
),
2
) + COS(39.862542 * PI() / 180) * COS(y_latitude * PI() / 180) * POW(
SIN(
(
116.434651 * PI() / 180 - x_longitude * PI() / 180
) / 2
),
2
)
)
) * 1000
) AS juli
FROM
t_organ
ORDER BY
juli ASC
延伸阅读: